What is the derivative of x^2+x-2 ?

The derivative of x^2+x-2 is 2x+1

What is the first derivative of x^2+x-2 ?

The first derivative of x^2+x-2 is 2x+1

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\frac{d}{d x} (x^{2} + x - 2)

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (2) = 0

= 2 x + 1 - 0

Simplify

= 2 x + 1

x \to 5 lim (\frac{x}{0})

\frac{d}{d x} (cos (x) x^{2})

\int \frac{1}{x ^{2} - 4 x + 6} d x

\frac{d y}{d x}, x^{2} + y^{2} = (2 x^{2} + 4 y^{2} - x) 2

\frac{d y}{d x} = 2 (2 x + y)^{2}

What is the derivative of x^2+x-2 ?
The derivative of x^2+x-2 is 2x+1
What is the first derivative of x^2+x-2 ?
The first derivative of x^2+x-2 is 2x+1