What is the limit as x approaches-1 of 1/(x^2+2x+1) ?

The limit as x approaches-1 of 1/(x^2+2x+1) is infinity

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limit as x approaches-1 of 1/(x^2+2x+1)

x \to - 1 lim (\frac{1}{x ^{2} + 2 x + 1})

\infty

Solution steps

x \to - 1 lim (\frac{1}{x ^{2} + 2 x + 1})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 1 - lim (\frac{1}{x ^{2} + 2 x + 1}) = \infty

x \to - 1 + lim (\frac{1}{x ^{2} + 2 x + 1}) = \infty

= \infty

4^{s i n (x)}

sin (2 x) d x + cos (7 y) d y = 0, y (π^{2}) = π^{7}

\frac{d}{d x} (\frac{x}{5})

\frac{\partial}{\partial x} (y - x)

y^{^{''}} + 16 y = 8 sin (4 x)

What is the limit as x approaches-1 of 1/(x^2+2x+1) ?
The limit as x approaches-1 of 1/(x^2+2x+1) is infinity