What is the tangent of (x-6/x),\at m=0 ?

The tangent of (x-6/x),\at m=0 is y=(1+6/(m^2))x-(12)/m

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tangent of (x-6/x),\at m=0

tangent of

(x - \frac{6}{x}), at m = 0

y = (1 + \frac{6}{m ^{2}}) x - \frac{12}{m}

Solution steps

Compute the tangent line to the general point

x = m

Find the tangent point:

(m, m - \frac{6}{m})

Find the slope of

y = (x - \frac{6}{x}) : \frac{d y}{d x} = 1 + \frac{6}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1 + \frac{6}{m ^{2}}

Find the line with slope m=

1 + \frac{6}{m ^{2}}

and passing through

(m, m - \frac{6}{m}) : y = (1 + \frac{6}{m ^{2}}) x - \frac{12}{m}

y = (1 + \frac{6}{m ^{2}}) x - \frac{12}{m}

x^{8} e^{7 x}

f (x) = \frac{x - 1}{x - 4}, at x = 5

\int cos^{2} (x) + cos (x) d x

\frac{d}{d x} (e^{\frac{2 x}{3}})

x \to 0 - lim (2 x^{2} sin (\frac{1}{x}))

What is the tangent of (x-6/x),\at m=0 ?
The tangent of (x-6/x),\at m=0 is y=(1+6/(m^2))x-(12)/m