What is the tangent of f(x)=5x^2,\at x=-3,-45 ?

The tangent of f(x)=5x^2,\at x=-3,-45 is y=-30x-45

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=5x^2,\at x=-3,-45

tangent of

f (x) = 5 x^{2}, at x = - 3, - 45

y = - 30 x - 45

Solution steps

Find the tangent point:

(- 3, 45)

Find the slope of

f (x) = 5 x^{2} : \frac{df ( x )}{d x} = 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 30

Find the line with slope m=

- 30

and passing through

(- 3, 45) : y = - 30 x - 45

y = - 30 x - 45

f (x) = x^{3} - 4 x

\frac{d}{d x} (\frac{sin ( x ^{2} )}{3 x})

\int x e^{x} d x

2 x y^{^{'}} + y = 6 x, y (4) = 26

f (x) = \frac{1}{x}

What is the tangent of f(x)=5x^2,\at x=-3,-45 ?
The tangent of f(x)=5x^2,\at x=-3,-45 is y=-30x-45