What is the derivative of x^2+4x-2 ?

The derivative of x^2+4x-2 is 2x+4

What is the first derivative of x^2+4x-2 ?

The first derivative of x^2+4x-2 is 2x+4

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derivative of

x^{2} + 4 x - 2

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (2) = 0

= 2 x + 4 - 0

Simplify

= 2 x + 4

f (t) = e^{2 t} cos (3 t)

n = 1 \sum \infty 2^{- n} + 3^{- n}

- 9 x^{\frac{1}{3}} + 5, at x = 4

\frac{\partial}{\partial z} (ln (x + z) - yz)

64 y^{^{''}} + 80 y^{^{'}} + 25 y = 0

What is the derivative of x^2+4x-2 ?
The derivative of x^2+4x-2 is 2x+4
What is the first derivative of x^2+4x-2 ?
The first derivative of x^2+4x-2 is 2x+4