What is the limit as x approaches 0+of-1/(x^2) ?

The limit as x approaches 0+of-1/(x^2) is -infinity

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limit as x approaches 0+of-1/(x^2)

x \to 0 + lim (- \frac{1}{x ^{2}})

- \infty

Solution steps

x \to 0 + lim (- \frac{1}{x ^{2}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 0 + lim (\frac{1}{x ^{2}})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= - \infty

y^{^{''}} - 5 y^{^{'}} + 9 y = x e^{x}

\frac{d}{d x} ((x^{2} - 2 x - 1)^{\frac{2}{3}})

\int tan^{5} (x) d x

(x + y) e^{\frac{x}{y}} d x + (x - \frac{x ^{2}}{y}) e^{\frac{x}{y}} d y = 0

\int (5 x^{14} - 2 x^{5}) d x

What is the limit as x approaches 0+of-1/(x^2) ?
The limit as x approaches 0+of-1/(x^2) is -infinity