integral of 9x^3y+3y^2

Lösung

\int 9 x^{3} y + 3 y^{2} d x

3 y^{2} x + \frac{9 y x ^{4}}{4} + C

Schritte zur Lösung

\int 9 x^{3} y + 3 y^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 y^{2} d x + \int 9 y x^{3} d x

\int 3 y^{2} d x = 3 y^{2} x

\int 9 y x^{3} d x = \frac{9 y x ^{4}}{4}

= 3 y^{2} x + \frac{9 y x ^{4}}{4}

Füge eine Konstante zur Lösung hinzu

= 3 y^{2} x + \frac{9 y x ^{4}}{4} + C

x \to 0 - lim (4 (\frac{1}{x} - csc (x)))

\frac{d}{d x} ((\frac{1}{3}) (x^{2} + 2)^{\frac{3}{2}})

\frac{\partial}{\partial x} (2 y - x^{2} e^{- y})

l a pl a ce t r an s f or m t^{3} e^{b \cdot t}

\frac{\partial}{\partial x} (ln (x + y^{4}))