What is area sqrt(x+8),x=0,y=0 ?

The answer to area sqrt(x+8),x=0,y=0 is (32sqrt(2))/3

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area sqrt(x+8),x=0,y=0

area

x + 8, x = 0, y = 0

\frac{32 2}{3}

Decimal

15.08494 \dots

Solution steps

Apply the area formula:

\int_{- 8}^{0} x + 8 d x

Solve

\int_{- 8}^{0} x + 8 d x : \frac{32 2}{3}

The area is:

= \frac{32 2}{3}

y = \frac{x + x ^{2}}{e ^{x} + 1}

\frac{d}{d x} (\frac{54}{x ^{4}})

\int 2 x + 4 x^{2} - \frac{5}{2} d x

\int \frac{x ^{2}}{2 ( 2 - x )} d x

x \to 0 lim (\frac{- 1}{14 x})

What is area sqrt(x+8),x=0,y=0 ?
The answer to area sqrt(x+8),x=0,y=0 is (32sqrt(2))/3