What is the derivative of y=cos(a^9+x^9) ?

The derivative of y=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8

What is the first derivative of y=cos(a^9+x^9) ?

The first derivative of y=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8

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derivative of

y = cos (a^{9} + x^{9})

- sin (a^{9} + x^{9}) \cdot 9 x^{8}

Solution steps

\frac{d}{d x} (cos (a^{9} + x^{9}))

Apply the chain rule:

- sin (a^{9} + x^{9}) \frac{d}{d x} (a^{9} + x^{9})

= - sin (a^{9} + x^{9}) \frac{d}{d x} (a^{9} + x^{9})

\frac{d}{d x} (a^{9} + x^{9}) = 9 x^{8}

= - sin (a^{9} + x^{9}) \cdot 9 x^{8}

y = 6 x^{2} - 3 x, at 1, 5

(8.1) (4.1)

\frac{\partial}{\partial y} (x^{4} + 2 x^{2} y)

\frac{d}{d x} ((x^{2} + 1)^{\frac{1}{2}})

n = 0 \sum \infty n \cdot sin (n \cdot π)

What is the derivative of y=cos(a^9+x^9) ?
The derivative of y=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8
What is the first derivative of y=cos(a^9+x^9) ?
The first derivative of y=cos(a^9+x^9) is -sin(a^9+x^9)*9x^8