What is (d^2)/(dx^2)(3x^2cos(8x)) ?

The answer to (d^2)/(dx^2)(3x^2cos(8x)) is 3(2cos(8x)-32xsin(8x)-64x^2cos(8x))

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(d^2)/(dx^2)(3x^2cos(8x))

\frac{d ^{2}}{d x ^{2}} (3 x^{2} cos (8 x))

3 (2 cos (8 x) - 32 x sin (8 x) - 64 x^{2} cos (8 x))

Solution steps

\frac{d ^{2}}{d x ^{2}} (3 x^{2} cos (8 x))

\frac{d}{d x} (3 x^{2} cos (8 x)) = 3 (2 x cos (8 x) - 8 x^{2} sin (8 x))

= \frac{d}{d x} (3 (2 x cos (8 x) - 8 x^{2} sin (8 x)))

\frac{d}{d x} (3 (2 x cos (8 x) - 8 x^{2} sin (8 x))) = 3 (2 cos (8 x) - 32 x sin (8 x) - 64 x^{2} cos (8 x))

= 3 (2 cos (8 x) - 32 x sin (8 x) - 64 x^{2} cos (8 x))

x \to 1 lim ((ln (x))^{x - 1})

\frac{d y}{d x} = 9 x^{2} - 12 x

\frac{1}{( s - 1 ) ( s - 2 ) ( s - 3 )}

e^{4 x^{3} - 18 x^{2}}

\frac{\partial}{\partial y} (3 x^{2} y + 2 x y^{2})

What is (d^2)/(dx^2)(3x^2cos(8x)) ?
The answer to (d^2)/(dx^2)(3x^2cos(8x)) is 3(2cos(8x)-32xsin(8x)-64x^2cos(8x))