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Popular >

integral of (2x+1)^2

Solution

\int (2 x + 1)^{2} d x

Solution

\frac{4 x ^{3}}{3} + 2 x^{2} + x + C

Solution steps

\int (2 x + 1)^{2} d x

Expand

(2 x + 1)^{2} : 4 x^{2} + 4 x + 1

= \int 4 x^{2} + 4 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{2} d x + \int 4 x d x + \int 1 d x

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 4 x d x = 2 x^{2}

\int 1 d x = x

= \frac{4 x ^{3}}{3} + 2 x^{2} + x

Add a constant to the solution

= \frac{4 x ^{3}}{3} + 2 x^{2} + x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of (2x+1)^2 ?
The integral of (2x+1)^2 is (4x^3)/3+2x^2+x+C