What is the integral of sin^9(x)cos(x) ?

The integral of sin^9(x)cos(x) is (sin^{10}(x))/(10)+C

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integral of sin^9(x)cos(x)

\int sin^{9} (x) cos (x) d x

\frac{sin ^{10} ( x )}{10} + C

Solution steps

\int sin^{9} (x) cos (x) d x

Apply u-substitution

: \int u^{9} d u

= \int u^{9} d u

Apply the Power Rule

: \frac{u ^{10}}{10}

= \frac{u ^{10}}{10}

Substitute back

u = sin (x)

= \frac{sin ^{10} ( x )}{10}

Add a constant to the solution

= \frac{sin ^{10} ( x )}{10} + C

\int \frac{sin ( π x )}{π} d x

\frac{\partial}{\partial g} (2 π \frac{l}{g})

(t - 1)^{2}

\int e^{4 l n (x)} d x

\frac{d}{d x} (\frac{x ^{3}}{2})

What is the integral of sin^9(x)cos(x) ?
The integral of sin^9(x)cos(x) is (sin^{10}(x))/(10)+C