What is the tangent of f(x)=7sqrt(x),\at x=25 ?

The tangent of f(x)=7sqrt(x),\at x=25 is y= 7/10 x+35/2

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tangent of f(x)=7sqrt(x),\at x=25

tangent of

f (x) = 7 x, at x = 25

y = \frac{7}{10} x + \frac{35}{2}

Solution steps

Find the tangent point:

(25, 35)

Find the slope of

f (x) = 7 x : \frac{df ( x )}{d x} = \frac{7}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(25, 35) : y = \frac{7}{10} x + \frac{35}{2}

y = \frac{7}{10} x + \frac{35}{2}

ln (x^{\frac{3}{2}})

\frac{10}{s ( s + 2 )}

f (x) = 4 x^{2} + 5 x + 1, (0, 1)

y = \frac{4 - 3 x}{3 x ^{2} + x}

630 - 4.9 t^{2}

What is the tangent of f(x)=7sqrt(x),\at x=25 ?
The tangent of f(x)=7sqrt(x),\at x=25 is y= 7/10 x+35/2