What is the tangent of y=(x^2)/(x+9),(1, 1/10) ?

The tangent of y=(x^2)/(x+9),(1, 1/10) is y= 19/100 x-9/100

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tangent of y=(x^2)/(x+9),(1, 1/10)

tangent of

y = \frac{x ^{2}}{x + 9}, (1, \frac{1}{10})

y = \frac{19}{100} x - \frac{9}{100}

Solution steps

Find the slope of

y = \frac{x ^{2}}{x + 9} : \frac{d y}{d x} = \frac{x ^{2} + 18 x}{( x + 9 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{19}{100}

Find the line with slope m=

\frac{19}{100}

and passing through

(1, \frac{1}{10}) : y = \frac{19}{100} x - \frac{9}{100}

y = \frac{19}{100} x - \frac{9}{100}

\frac{\partial}{\partial x} ((x y^{2} + x^{3})^{4})

x \to 2 lim (x^{3} - 3 x + 7)

\frac{d}{d x} (\frac{x}{5 - x ^{2}})

\frac{\partial}{\partial x} (A e^{x})

x \to 4 - lim (\frac{1}{x ^{3} - 64})

What is the tangent of y=(x^2)/(x+9),(1, 1/10) ?
The tangent of y=(x^2)/(x+9),(1, 1/10) is y= 19/100 x-9/100