What is the solution for (dy)/(dx)=(y+1)^{-1} ?

The solution for (dy)/(dx)=(y+1)^{-1} is y=-1+sqrt(2(x+c_{1))+1},y=-sqrt(2(x+c_{1))+1}-1

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(dy)/(dx)=(y+1)^{-1}

\frac{d y}{d x} = (y + 1)^{- 1}

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

Solution steps

\frac{d y}{d x} = (y + 1)^{- 1}

Solve separable ODE:

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

y = - 1 + 2 (x + c_{1}) + 1, y = - 2 (x + c_{1}) + 1 - 1

\frac{d}{d x} (4 e^{x} + \frac{8}{3 x})

\int_{1}^{8} \frac{x}{x ^{2} + 6 x + 13} d x

x \to 0 lim (ln^{4} (x) x)

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\frac{d}{d x} (x^{2} e^{k x})

What is the solution for (dy)/(dx)=(y+1)^{-1} ?
The solution for (dy)/(dx)=(y+1)^{-1} is y=-1+sqrt(2(x+c_{1))+1},y=-sqrt(2(x+c_{1))+1}-1