What is the tangent of x^2-5x+5 ?

The tangent of x^2-5x+5 is y=(2a_{0}-5)x-a_{0}^2+5

Popular >

tangent of x^2-5x+5

tangent of

x^{2} - 5 x + 5

y = (2 a_{0} - 5) x - a_{0}^{2} + 5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 5 a_{0} + 5)

Find the slope of

y = x^{2} - 5 x + 5 : \frac{d y}{d x} = 2 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a_{0} - 5

Find the line with slope m=

2 a_{0} - 5

and passing through

(a_{0}, a_{0}^{2} - 5 a_{0} + 5) : y = (2 a_{0} - 5) x - a_{0}^{2} + 5

y = (2 a_{0} - 5) x - a_{0}^{2} + 5

\frac{\partial}{\partial x} (y cos (x^{2} + y^{2}))

\frac{d}{d x} (\frac{- 1}{1 - x})

\frac{d}{d x} (\frac{x}{1 + 1 - x ^{2}})

\int \frac{1100 x}{x ^{2} + 80} d x

f (x) = x, (64, 8)

What is the tangent of x^2-5x+5 ?
The tangent of x^2-5x+5 is y=(2a_{0}-5)x-a_{0}^2+5