What is the derivative of f(x)=6x^3+7 ?

The derivative of f(x)=6x^3+7 is 18x^2

What is the first derivative of f(x)=6x^3+7 ?

The first derivative of f(x)=6x^3+7 is 18x^2

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derivative of

f (x) = 6 x^{3} + 7

18 x^{2}

Solution steps

\frac{d}{d x} (6 x^{3} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x^{3}) + \frac{d}{d x} (7)

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (7) = 0

= 18 x^{2} + 0

Simplify

= 18 x^{2}

\int 6 e^{6 x} sin (e^{6 x}) d x

\int \frac{1}{4 y ^{2}} d y

\frac{x + 1}{x + 3}

y = (2 x^{2} + 3) (4 x - 3)

\frac{x}{6 + x}

What is the derivative of f(x)=6x^3+7 ?
The derivative of f(x)=6x^3+7 is 18x^2
What is the first derivative of f(x)=6x^3+7 ?
The first derivative of f(x)=6x^3+7 is 18x^2