What is (\partial)/(\partial x)(3x-sqrt(2y^2+z^2)) ?

The answer to (\partial)/(\partial x)(3x-sqrt(2y^2+z^2)) is 3

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(\partial)/(\partial x)(3x-sqrt(2y^2+z^2))

\frac{\partial}{\partial x} (3 x - 2 y^{2} + z^{2})

3

Solution steps

\frac{\partial}{\partial x} (3 x - 2 y^{2} + z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x) - \frac{\partial}{\partial x} (2 y^{2} + z^{2})

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (2 y^{2} + z^{2}) = 0

= 3 - 0

Simplify

= 3

\frac{d}{d x} (2 - \frac{x ^{2}}{2})

\int \frac{e ^{x}}{e ^{x} + 1 + 1} d x

\frac{\partial}{\partial y} (x^{4} - 2 y^{3})

\frac{d}{d x} (x - 2 arctan (x))

\frac{d}{d x} (4 x^{2} + 1)

What is (\partial)/(\partial x)(3x-sqrt(2y^2+z^2)) ?
The answer to (\partial)/(\partial x)(3x-sqrt(2y^2+z^2)) is 3