What is the derivative of 6/(sqrt(2x+1)) ?

The derivative of 6/(sqrt(2x+1)) is -6/((2x+1)^{3/2)}

What is the first derivative of 6/(sqrt(2x+1)) ?

The first derivative of 6/(sqrt(2x+1)) is -6/((2x+1)^{3/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{6}{2 x + 1})

- \frac{6}{( 2 x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{6}{2 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((2 x + 1)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 6 (- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \cdot 2)

Simplify

6 (- \frac{1}{2 ( 2 x + 1 ) ^{\frac{3}{2}}} \cdot 2) : - \frac{6}{( 2 x + 1 ) ^{\frac{3}{2}}}

= - \frac{6}{( 2 x + 1 ) ^{\frac{3}{2}}}

tan^{3} (x)

\frac{d}{d x} (\frac{150}{x})

\frac{d y}{d x} = 4 x

e^{1}

\frac{d}{d x} (- sinh (x))

What is the derivative of 6/(sqrt(2x+1)) ?
The derivative of 6/(sqrt(2x+1)) is -6/((2x+1)^{3/2)}
What is the first derivative of 6/(sqrt(2x+1)) ?
The first derivative of 6/(sqrt(2x+1)) is -6/((2x+1)^{3/2)}