What is the tangent of y=600-(x^2)/(121) ?

The tangent of y=600-(x^2)/(121) is y=-(2a_{0})/(121)x+600+(a_{0}^2)/(121)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=600-(x^2)/(121)

tangent of

y = 600 - \frac{x ^{2}}{121}

y = - \frac{2 a _{0}}{121} x + 600 + \frac{a _{0}^{2}}{121}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 600 - \frac{a _{0}^{2}}{121})

Find the slope of

y = 600 - \frac{x ^{2}}{121} : \frac{d y}{d x} = - \frac{2 x}{121}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2 a _{0}}{121}

Find the line with slope m=

- \frac{2 a _{0}}{121}

and passing through

(a_{0}, 600 - \frac{a _{0}^{2}}{121}) : y = - \frac{2 a _{0}}{121} x + 600 + \frac{a _{0}^{2}}{121}

y = - \frac{2 a _{0}}{121} x + 600 + \frac{a _{0}^{2}}{121}

x^{^{'}} = x - x^{2}

\frac{d}{d x} (e^{2 x} + e^{- 2 x})

\int e^{i wt + ib t} d t

x \to 3 lim (x + 4)

x \to 1 lim (\frac{x ^{n} - 1}{x - 1})

What is the tangent of y=600-(x^2)/(121) ?
The tangent of y=600-(x^2)/(121) is y=-(2a_{0})/(121)x+600+(a_{0}^2)/(121)