What is the solution for (dr)/(dθ)=(r^2+9rθ^2)/(3θ^3) ?

The solution for (dr)/(dθ)=(r^2+9rθ^2)/(3θ^3) is r(θ)=(3θ^3)/(-θ+c_{1)}

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(dr)/(dθ)=(r^2+9rθ^2)/(3θ^3)

\frac{d r}{d θ} = \frac{r ^{2} + 9 r θ ^{2}}{3 θ ^{3}}

r (θ) = \frac{3 θ ^{3}}{- θ + c _{1}}

Solution steps

\frac{d r}{d θ} = \frac{r ^{2} + 9 r θ ^{2}}{3 θ ^{3}}

Solve Bernoulli ODE:

r (θ) = \frac{3 θ ^{3}}{- θ + c _{1}}

r (θ) = \frac{3 θ ^{3}}{- θ + c _{1}}

\int_{0}^{1} 9 cos (3 x) d x

\int \frac{1}{( x + 3 ) x ^{2} + 6 x} d x

f (x) = \frac{x}{7} - 1

\int \frac{3 x - 2}{x ^{2} - x - 3} d x

\int 14 x - x^{2} d x

What is the solution for (dr)/(dθ)=(r^2+9rθ^2)/(3θ^3) ?
The solution for (dr)/(dθ)=(r^2+9rθ^2)/(3θ^3) is r(θ)=(3θ^3)/(-θ+c_{1)}