What is the integral of sinh^2(x)cosh(x) ?

The integral of sinh^2(x)cosh(x) is (sinh^3(x))/3+C

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integral of sinh^2(x)cosh(x)

\int sinh^{2} (x) cosh (x) d x

\frac{sinh ^{3} ( x )}{3} + C

Solution steps

\int sinh^{2} (x) cosh (x) d x

Apply u-substitution

: \int u^{2} d u

= \int u^{2} d u

Apply the Power Rule

: \frac{u ^{3}}{3}

= \frac{u ^{3}}{3}

Substitute back

u = sinh (x)

= \frac{sinh ^{3} ( x )}{3}

Add a constant to the solution

= \frac{sinh ^{3} ( x )}{3} + C

x \to 0 lim (x cos (\frac{1}{x ^{2}}))

\int (1 - x^{3})^{2} x d x

\int x e^{- 5 x^{2}} d x

\int (2 x + 4) (x^{2} + 4 x + 10)^{4} d x

\int x^{5} x^{3} + 3 d x

What is the integral of sinh^2(x)cosh(x) ?
The integral of sinh^2(x)cosh(x) is (sinh^3(x))/3+C