What is the slope of y=(x^2-3)^4,\at x=2 ?

The slope of y=(x^2-3)^4,\at x=2 is 16

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slope of y=(x^2-3)^4,\at x=2

slope

y = (x^{2} - 3)^{4}, at x = 2

16

Solution steps

y = (x^{2} - 3)^{4}

In order to find the slope of the function, take the derivative of

(x^{2} - 3)^{4}

\frac{d}{d x} ((x^{2} - 3)^{4}) = 8 x (x^{2} - 3)^{3}

8 x (x^{2} - 3)^{3}

Find the value of

8 x (x^{2} - 3)^{3}

for

x = 2 : 16

16

\frac{d}{d x} (x^{\frac{x}{2}})

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\int_{0}^{4} 2 π x (x) d x

What is the slope of y=(x^2-3)^4,\at x=2 ?
The slope of y=(x^2-3)^4,\at x=2 is 16