What is area f(x)=x^2,g(x)=sqrt(9+x) ?

The answer to area f(x)=x^2,g(x)=sqrt(9+x) is 6.93623…

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area f(x)=x^2,g(x)=sqrt(9+x)

area

f (x) = x^{2}, g (x) = 9 + x

6.93623 \dots

Solution steps

Apply the area formula:

\int_{- 1.64672 \dots}^{1.81338 \dots} x^{2} - 9 + x d x

Solve

\int_{- 1.64672 \dots}^{1.81338 \dots} x^{2} - 9 + x d x : 6.93623 \dots

The area is:

= 6.93623 \dots

f (x) = 1 8^{x}

\int \frac{y}{y ^{2} + 2} d y

\int (10 x - 3) d x

x^{2} - 3 x + 2, - 3 x + 3

\frac{( t - 3 t )}{t}

What is area f(x)=x^2,g(x)=sqrt(9+x) ?
The answer to area f(x)=x^2,g(x)=sqrt(9+x) is 6.93623…