What is the derivative of sqrt(16+x^2) ?

The derivative of sqrt(16+x^2) is x/(sqrt(16+x^2))

What is the first derivative of sqrt(16+x^2) ?

The first derivative of sqrt(16+x^2) is x/(sqrt(16+x^2))

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\frac{d}{d x} (16 + x^{2})

\frac{x}{16 + x ^{2}}

Solution steps

\frac{d}{d x} (16 + x^{2})

Apply the chain rule:

\frac{1}{2 16 + x ^{2}} \frac{d}{d x} (16 + x^{2})

= \frac{1}{2 16 + x ^{2}} \frac{d}{d x} (16 + x^{2})

\frac{d}{d x} (16 + x^{2}) = 2 x

= \frac{1}{2 16 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 16 + x ^{2}} \cdot 2 x : \frac{x}{16 + x ^{2}}

= \frac{x}{16 + x ^{2}}

\frac{d}{d x} (a x cos (3 x))

n = 1 \sum \infty \frac{1}{2 ^{n} + 3 ^{n}}

x y^{2} (\frac{d y}{d x}) = y^{3} - x^{3}

\int (2 x y^{2} + 2 y) d x

x y^{^{'}} + 2 y = 3 x

What is the derivative of sqrt(16+x^2) ?
The derivative of sqrt(16+x^2) is x/(sqrt(16+x^2))
What is the first derivative of sqrt(16+x^2) ?
The first derivative of sqrt(16+x^2) is x/(sqrt(16+x^2))