What is the derivative of 2e^{4x}+x ?

The derivative of 2e^{4x}+x is 8e^{4x}+1

What is the first derivative of 2e^{4x}+x ?

The first derivative of 2e^{4x}+x is 8e^{4x}+1

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\frac{d}{d x} (2 e^{4 x} + x)

8 e^{4 x} + 1

Solution steps

\frac{d}{d x} (2 e^{4 x} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 e^{4 x}) + \frac{d x}{d x}

\frac{d}{d x} (2 e^{4 x}) = 8 e^{4 x}

\frac{d x}{d x} = 1

= 8 e^{4 x} + 1

\frac{d}{d x} (2 e^{x} - 3 x^{2} x)

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What is the derivative of 2e^{4x}+x ?
The derivative of 2e^{4x}+x is 8e^{4x}+1
What is the first derivative of 2e^{4x}+x ?
The first derivative of 2e^{4x}+x is 8e^{4x}+1