What is the sum from n=1 to infinity of n^2(-1)^n ?

The sum from n=1 to infinity of n^2(-1)^n is diverges

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sum from n=1 to infinity of n^2(-1)^n

n = 1 \sum \infty n^{2} (- 1)^{n}

diverges

Solution steps

n = 1 \sum \infty n^{2} (- 1)^{n}

Apply Series Divergence Test:

diverges

= diverges

f (x) = x^{2} + x, (- 3, 1)

f (x) = \frac{e ^{x}}{4 x ^{2} + 1}

\int \frac{1}{x ( a ^{2} - x ^{2} )} d x

\int \frac{1}{4 + 9 x ^{2}} d x

\frac{d y}{d x} - 4 y = x^{2} + 9

What is the sum from n=1 to infinity of n^2(-1)^n ?
The sum from n=1 to infinity of n^2(-1)^n is diverges