What is the derivative of sin^2(8x) ?

The derivative of sin^2(8x) is 16sin(8x)cos(8x)

What is the first derivative of sin^2(8x) ?

The first derivative of sin^2(8x) is 16sin(8x)cos(8x)

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\frac{d}{d x} (sin^{2} (8 x))

16 sin (8 x) cos (8 x)

Solution steps

\frac{d}{d x} (sin^{2} (8 x))

Apply the chain rule:

2 sin (8 x) \frac{d}{d x} (sin (8 x))

= 2 sin (8 x) \frac{d}{d x} (sin (8 x))

\frac{d}{d x} (sin (8 x)) = cos (8 x) \cdot 8

= 2 sin (8 x) cos (8 x) \cdot 8

Simplify

= 16 sin (8 x) cos (8 x)

\frac{d y}{d x} + x y = x y^{2}

\frac{d}{d x} (- cos (cos (x)) sin (x))

\int x^{3} sin^{2} (x) d x

\int_{\frac{π}{4}}^{\frac{π}{3}} 1

\frac{\partial}{\partial x} (2 x y + x^{2} + 3 y^{2})

What is the derivative of sin^2(8x) ?
The derivative of sin^2(8x) is 16sin(8x)cos(8x)
What is the first derivative of sin^2(8x) ?
The first derivative of sin^2(8x) is 16sin(8x)cos(8x)