What is the integral from 2 to infinity of e^{-2p} ?

The integral from 2 to infinity of e^{-2p} is 1/(2e^4)

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integral from 2 to infinity of e^{-2p}

\int_{2}^{\infty} e^{- 2 p} d p

\frac{1}{2 e ^{4}}

Decimal

0.00915 \dots

Solution steps

\int_{2}^{\infty} e^{- 2 p} d p

Compute the indefinite integral:

\int e^{- 2 p} d p = - \frac{1}{2} e^{- 2 p} + C

Compute the boundaries:

\int_{2}^{\infty} e^{- 2 p} d p = 0 - (- \frac{1}{2 e ^{4}})

= 0 - (- \frac{1}{2 e ^{4}})

Simplify

= \frac{1}{2 e ^{4}}

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What is the integral from 2 to infinity of e^{-2p} ?
The integral from 2 to infinity of e^{-2p} is 1/(2e^4)