What is the solution for (dy)/(dt)= 1/((2y+1)) ?

The solution for (dy)/(dt)= 1/((2y+1)) is y=(-1+sqrt(1-4(-c_{1)-t)})/2 ,y=(-1-sqrt(1-4(-c_{1)-t)})/2

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(dy)/(dt)= 1/((2y+1))

\frac{d y}{d t} = \frac{1}{( 2 y + 1 )}

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

Solution steps

\frac{d y}{d t} = \frac{1}{( 2 y + 1 )}

Solve separable ODE:

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

y = \frac{- 1 + 1 - 4 ( - c _{1} - t )}{2}, y = \frac{- 1 - 1 - 4 ( - c _{1} - t )}{2}

3 \cdot e^{- 2 t} + 2 \cdot sin (3 t)

\int_{- 16}^{0} \frac{1}{9 - x} d x

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x \to 0 lim (\frac{x - 15}{x - 5})

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What is the solution for (dy)/(dt)= 1/((2y+1)) ?
The solution for (dy)/(dt)= 1/((2y+1)) is y=(-1+sqrt(1-4(-c_{1)-t)})/2 ,y=(-1-sqrt(1-4(-c_{1)-t)})/2