What is (\partial)/(\partial x)(y^2-x^3-2x) ?

The answer to (\partial)/(\partial x)(y^2-x^3-2x) is -3x^2-2

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(\partial)/(\partial x)(y^2-x^3-2x)

\frac{\partial}{\partial x} (y^{2} - x^{3} - 2 x)

- 3 x^{2} - 2

Solution steps

\frac{\partial}{\partial x} (y^{2} - x^{3} - 2 x)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (2 x) = 2

= 0 - 3 x^{2} - 2

Simplify

= - 3 x^{2} - 2

y = \frac{( x + 8 )}{( x - 5 )}

(x^{2} - 1) cos (3 x)

x \to - 7 + lim (- \frac{8 x}{x + 7})

\frac{d}{d x} (\frac{3 x ^{2}}{2})

- 0.7 x^{2}

What is (\partial)/(\partial x)(y^2-x^3-2x) ?
The answer to (\partial)/(\partial x)(y^2-x^3-2x) is -3x^2-2