What is the tangent of y=6sqrt(x)(9.18) ?

The tangent of y=6sqrt(x)(9.18) is y=(27.54)/(sqrt(a_{0))}x+(1377sqrt(a_{0)})/(50)

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tangent of y=6sqrt(x)(9.18)

tangent of

y = 6 x (9.18)

y = \frac{27.54}{a _{0}} x + \frac{1377 a _{0}}{50}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 55.08 a_{0})

Find the slope of

y = 6 x 9.18 : \frac{d y}{d x} = \frac{27.54}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{27.54}{a _{0}}

Find the line with slope m=

\frac{27.54}{a _{0}}

and passing through

(a_{0}, 55.08 a_{0}) : y = \frac{27.54}{a _{0}} x + \frac{1377 a _{0}}{50}

y = \frac{27.54}{a _{0}} x + \frac{1377 a _{0}}{50}

\frac{d}{d x} (\frac{2 x ^{5} + x ^{2} - 5}{x ^{2}})

x \to \infty lim (2 x^{2} - 3 x)

\frac{d}{d x} (a x cos (x))

\int sin^{5} (1) d x

(- 9, 7), (- 6, - 3)

What is the tangent of y=6sqrt(x)(9.18) ?
The tangent of y=6sqrt(x)(9.18) is y=(27.54)/(sqrt(a_{0))}x+(1377sqrt(a_{0)})/(50)