What is the derivative of x^3+3x^2+6x ?

The derivative of x^3+3x^2+6x is 3x^2+6x+6

What is the first derivative of x^3+3x^2+6x ?

The first derivative of x^3+3x^2+6x is 3x^2+6x+6

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\frac{d}{d x} (x^{3} + 3 x^{2} + 6 x)

3 x^{2} + 6 x + 6

Solution steps

\frac{d}{d x} (x^{3} + 3 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

= 3 x^{2} + 6 x + 6

y = ln (\frac{cos ( x )}{cos ( x ) - 1})

\int 3 x^{9} e^{- x^{5}} d x

\int \frac{x ^{2}}{x - 8} d x

\int_{- \infty}^{0} \frac{1}{x ^{2}} d x

e^{- y} (1 + \frac{d y}{d x}) = 1

What is the derivative of x^3+3x^2+6x ?
The derivative of x^3+3x^2+6x is 3x^2+6x+6
What is the first derivative of x^3+3x^2+6x ?
The first derivative of x^3+3x^2+6x is 3x^2+6x+6