What is the solution for derivative of (dy/(dx))+25y=0 ?

The solution for derivative of (dy/(dx))+25y=0 is y=c_{1}cos(5x)+c_{2}sin(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of (dy/(dx))+25y=0

\frac{d}{d x} (\frac{d y}{d x}) + 25 y = 0

y = c_{1} cos (5 x) + c_{2} sin (5 x)

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 25 y = 0

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x)

x \to 0 lim (\frac{sin ^{9} ( x )}{x})

\int x^{2} e^{x^{3} + 4} d x

f (x) = \frac{( x ^{2} - 1 )}{( x ^{2} + 1 )}

\frac{x + 9}{x - 9}

\int (\frac{2}{x} - \frac{1}{2}) d x

What is the solution for derivative of (dy/(dx))+25y=0 ?
The solution for derivative of (dy/(dx))+25y=0 is y=c_{1}cos(5x)+c_{2}sin(5x)