What is (\partial)/(\partial x)(9x^2cos(y^6)) ?

The answer to (\partial)/(\partial x)(9x^2cos(y^6)) is 18xcos(y^6)

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(\partial)/(\partial x)(9x^2cos(y^6))

\frac{\partial}{\partial x} (9 x^{2} cos (y^{6}))

18 x cos (y^{6})

Solution steps

\frac{\partial}{\partial x} (9 x^{2} cos (y^{6}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 cos (y^{6}) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 cos (y^{6}) \cdot 2 x^{2 - 1}

Simplify

= 18 x cos (y^{6})

\frac{d}{d x} (4 3 x + 2 ln (x) - 3 e^{x})

\frac{d}{d x} (\frac{5 x ^{4} + 2 x}{2 x ^{9}})

\int \frac{5 ^{x}}{5 ^{x} - 1} d x

x \to 0 lim (\frac{( 4 + x ) - 16}{x})

f (x) = \frac{5}{6 x ^{5}}

What is (\partial)/(\partial x)(9x^2cos(y^6)) ?
The answer to (\partial)/(\partial x)(9x^2cos(y^6)) is 18xcos(y^6)