What is the solution for y^{''}+by=0 ?

The solution for y^{''}+by=0 is y=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)

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y^{''}+by=0

y^{^{''}} + b y = 0

y = c_{1} cos (b t) + c_{2} sin (b t)

Solution steps

y^{''} (t) + b y (t) = 0

Solve linear ODE:

y = c_{1} cos (b t) + c_{2} sin (b t)

y = c_{1} cos (b t) + c_{2} sin (b t)

- 3 e^{2 t}

x \to - \infty lim (ln (- x))

x \to 3 + lim (\frac{x}{( 3 - x ) ^{2}})

\frac{\partial}{\partial x} (x y + z (x + 2 y - 1))

x + y = 2, y = x^{2}

What is the solution for y^{''}+by=0 ?
The solution for y^{''}+by=0 is y=c_{1}cos(sqrt(b)t)+c_{2}sin(sqrt(b)t)