What is (\partial)/(\partial x)(7ycos(x)) ?

The answer to (\partial)/(\partial x)(7ycos(x)) is -7ysin(x)

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(\partial)/(\partial x)(7ycos(x))

\frac{\partial}{\partial x} (7 y cos (x))

- 7 y sin (x)

Solution steps

\frac{\partial}{\partial x} (7 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 7 y (- sin (x))

Simplify

= - 7 y sin (x)

n = 2 \sum \infty \frac{5}{3 ^{n}}

- \frac{32}{( t ) ^{3}} + \frac{4}{( t ) ^{2}}

\frac{\partial}{\partial x} (2 x y^{3} + 4)

\frac{d y}{d x} = \frac{y + 2 x y}{x}

f (x) = r^{2} - 10 x^{2}

What is (\partial)/(\partial x)(7ycos(x)) ?
The answer to (\partial)/(\partial x)(7ycos(x)) is -7ysin(x)