What is the tangent of-3cos(x) ?

The tangent of-3cos(x) is y=3sin(a_{0})x-3cos(a_{0})-3sin(a_{0})a_{0}

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tangent of-3cos(x)

tangent of

- 3 cos (x)

y = 3 sin (a_{0}) x - 3 cos (a_{0}) - 3 sin (a_{0}) a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 cos (a_{0}))

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3 sin (a_{0})

Find the line with slope m=

3 sin (a_{0})

and passing through

(a_{0}, - 3 cos (a_{0})) : y = 3 sin (a_{0}) x - 3 cos (a_{0}) - 3 sin (a_{0}) a_{0}

y = 3 sin (a_{0}) x - 3 cos (a_{0}) - 3 sin (a_{0}) a_{0}

y = tan (x), y = 2 sin (x)

\int cot^{4} (2 t) d t

\frac{d}{d x} (\frac{( x ^{2} - 4 ) ^{3}}{x ^{2} + 2})

f (X) = ln (ln (ln (tan (X))))

\frac{\partial}{\partial x} (y \cdot ln (x) + \frac{1}{9} y^{3})

What is the tangent of-3cos(x) ?
The tangent of-3cos(x) is y=3sin(a_{0})x-3cos(a_{0})-3sin(a_{0})a_{0}