What is the integral of cos^2(8x) ?

The integral of cos^2(8x) is 1/2 (x+1/16 sin(16x))+C

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integral of cos^2(8x)

\int cos^{2} (8 x) d x

\frac{1}{2} (x + \frac{1}{16} sin (16 x)) + C

Solution steps

\int cos^{2} (8 x) d x

Rewrite using trig identities

= \int \frac{1}{2} (1 + cos (16 x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int 1 + cos (16 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int 1 d x + \int cos (16 x) d x)

\int 1 d x = x

\int cos (16 x) d x = \frac{1}{16} sin (16 x)

= \frac{1}{2} (x + \frac{1}{16} sin (16 x))

Add a constant to the solution

= \frac{1}{2} (x + \frac{1}{16} sin (16 x)) + C

\int θ^{2} d θ

n = 1 \sum \infty (- 1)^{n} n^{2}

\int \frac{5 x ^{2} - 9}{x ^{3} - 9 x} d x

f (x) = \frac{x - 5}{x + 5}

f (x) = \frac{( 1 - 5 x )}{1 + 5 x}

What is the integral of cos^2(8x) ?
The integral of cos^2(8x) is 1/2 (x+1/16 sin(16x))+C