What is the slope of 3^{x^2-1},\at x=2 ?

The slope of 3^{x^2-1},\at x=2 is 108ln(3)

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slope of 3^{x^2-1},\at x=2

slope

3^{x^{2} - 1}, at x = 2

108 ln (3)

Solution steps

y = 3^{x^{2} - 1}

In order to find the slope of the function, take the derivative of

3^{x^{2} - 1}

\frac{d}{d x} (3^{x^{2} - 1}) = 2 ln (3) \cdot 3^{x^{2} - 1} x

2 ln (3) \cdot 3^{x^{2} - 1} x

Find the value of

2 ln (3) \cdot 3^{x^{2} - 1} x

for

x = 2 : 108 ln (3)

108 ln (3)

\int \frac{1}{3} d x

\int 4 x^{- 2} + 3 x^{- 1} - 1 d x

x \to 2 π lim (sin (x))

\int - \frac{1}{2} e^{- 2 v} d v

\frac{d y}{d x} = - \frac{1}{2} y + x

What is the slope of 3^{x^2-1},\at x=2 ?
The slope of 3^{x^2-1},\at x=2 is 108ln(3)