What is the d/(dθ)(4+4sin(θ)) ?

The d/(dθ)(4+4sin(θ)) is 4cos(θ)

What is the first d/(dθ)(4+4sin(θ)) ?

The first d/(dθ)(4+4sin(θ)) is 4cos(θ)

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\frac{d}{d θ} (4 + 4 sin (θ))

4 cos (θ)

Solution steps

\frac{d}{d θ} (4 + 4 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (4) + \frac{d}{d θ} (4 sin (θ))

\frac{d}{d θ} (4) = 0

\frac{d}{d θ} (4 sin (θ)) = 4 cos (θ)

= 0 + 4 cos (θ)

Simplify

= 4 cos (θ)

\frac{d}{d x} (x - 3 x^{\frac{1}{3}})

\frac{d}{d x} (cos (3 x) \cdot 3)

f (x) = \frac{x ^{3}}{3}

f (x) = x - e^{x}

\int_{2}^{3} x x - 2 d x