What is (\partial)/(\partial z)(22cos(x)yz^2) ?

The answer to (\partial)/(\partial z)(22cos(x)yz^2) is 44yzcos(x)

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(\partial)/(\partial z)(22cos(x)yz^2)

\frac{\partial}{\partial z} (22 cos (x) y z^{2})

44 yz cos (x)

Solution steps

\frac{\partial}{\partial z} (22 cos (x) y z^{2})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 22 cos (x) y \frac{\partial}{\partial z} (z^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 22 cos (x) y \cdot 2 z^{2 - 1}

Simplify

= 44 yz cos (x)

\int - \frac{1}{16} sin (4 x) d x

x \to 64 lim (x^{\frac{4}{3}})

y = x^{2} + 5 x, (- 4, - 4)

\frac{d}{d x} (x - \frac{x ^{2}}{800})

\frac{d}{d x} (x^{3} - 6 x + 12)

What is (\partial)/(\partial z)(22cos(x)yz^2) ?
The answer to (\partial)/(\partial z)(22cos(x)yz^2) is 44yzcos(x)