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Popular >

y-2y^'-24y=0

Solution

y - 2 y^{^{'}} - 24 y = 0

Solution

y = e^{\frac{- 23 t + c _{1}}{2}}

Solution steps

y - 2 y^{'} (t) - 24 y = 0

Solve separable ODE:

y = e^{\frac{- 23 t + c _{1}}{2}}

y = e^{\frac{- 23 t + c _{1}}{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y-2y^'-24y=0 ?
The solution for y-2y^'-24y=0 is y=e^{(-23t+c_{1})/2}