What is area 0.01x^2-3x+229,429-2x,x=0 ?

The answer to area 0.01x^2-3x+229,429-2x,x=0 is 45000

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 0.01x^2-3x+229,429-2x,x=0

area

0.01 x^{2} - 3 x + 229, 429 - 2 x, x = 0

45000

Solution steps

Apply the area formula:

\int_{- 100}^{200} 0.01 x^{2} - 3 x + 229 - (429 - 2 x) d x

Solve

\int_{- 100}^{200} 0.01 x^{2} - 3 x + 229 - (429 - 2 x) d x : 45000

The area is:

= 45000

\frac{\partial}{\partial x} (8 e^{x y} + 5)

- 0.5 x + 6, 0, 4, 8

\frac{d}{d x} (- 3 (e^{x})^{3})

\int x^{2} - \frac{1}{x} d x

ln (2) x^{5}

What is area 0.01x^2-3x+229,429-2x,x=0 ?
The answer to area 0.01x^2-3x+229,429-2x,x=0 is 45000