What is the sum from n=1 to infinity of 2-3(0.8)^n ?

The sum from n=1 to infinity of 2-3(0.8)^n is diverges

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sum from n=1 to infinity of 2-3(0.8)^n

n = 1 \sum \infty 2 - 3 (0.8)^{n}

diverges

Solution steps

n = 1 \sum \infty 2 - 3 \cdot 0. 8^{n}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of 2-3(0.8)^n ?
The sum from n=1 to infinity of 2-3(0.8)^n is diverges