What is the tangent of y=2ln(x),\at x=4 ?

The tangent of y=2ln(x),\at x=4 is y= 1/2 x+4ln(2)-2

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tangent of y=2ln(x),\at x=4

tangent of

y = 2 ln (x), at x = 4

y = \frac{1}{2} x + 4 ln (2) - 2

Solution steps

Find the tangent point:

(4, 4 ln (2))

Find the slope of

y = 2 ln (x) : \frac{d y}{d x} = \frac{2}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(4, 4 ln (2)) : y = \frac{1}{2} x + 4 ln (2) - 2

y = \frac{1}{2} x + 4 ln (2) - 2

\frac{\partial}{\partial x} (x y e^{- x y})

\frac{d}{d x} (ln (3 x + 2 y))

y^{^{''}} + 7 y^{^{'}} + 23 y = 0

x \to 2 lim (\frac{x ^{2} + 1}{x - 1})

\int \frac{2 z - 3}{7 z - 10} d z

What is the tangent of y=2ln(x),\at x=4 ?
The tangent of y=2ln(x),\at x=4 is y= 1/2 x+4ln(2)-2