What is (\partial)/(\partial x)(2sin(x)cos(y)) ?

The answer to (\partial)/(\partial x)(2sin(x)cos(y)) is 2cos(y)cos(x)

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(\partial)/(\partial x)(2sin(x)cos(y))

\frac{\partial}{\partial x} (2 sin (x) cos (y))

2 cos (y) cos (x)

Solution steps

\frac{\partial}{\partial x} (2 sin (x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 cos (y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= 2 cos (y) cos (x)

\frac{d}{d x} (\frac{x}{x ^{- 1} + 1})

\frac{\partial}{\partial x} (x^{3} y + 12 x^{2} - 64 y)

\int (3 + 3 tan^{2} (x)) d x

\frac{5 x ^{3}}{( 5 - 3 x ) ^{4}}

f (x) = 5 (x^{3} - x)^{4}

What is (\partial)/(\partial x)(2sin(x)cos(y)) ?
The answer to (\partial)/(\partial x)(2sin(x)cos(y)) is 2cos(y)cos(x)