What is the derivative of (5x/(x+4)) ?

The derivative of (5x/(x+4)) is (20)/((x+4)^2)

What is the first derivative of (5x/(x+4)) ?

The first derivative of (5x/(x+4)) is (20)/((x+4)^2)

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\frac{d}{d x} (\frac{5 x}{x + 4})

\frac{20}{( x + 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5 x}{x + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{x}{x + 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 5 \cdot \frac{\frac{d x}{d x} ( x + 4 ) - \frac{d}{d x} ( x + 4 ) x}{( x + 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 4) = 1

= 5 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}}

Simplify

5 \cdot \frac{1 \cdot ( x + 4 ) - 1 \cdot x}{( x + 4 ) ^{2}} : \frac{20}{( x + 4 ) ^{2}}

= \frac{20}{( x + 4 ) ^{2}}

\int_{- 4}^{4} (3 - ∣ x ∣) d x

y = (x^{2} + 4)^{\frac{2}{3}}, at x = 2

y = 5 ln (4 x^{2} + 1)

\int t e^{4 t} d t

\int \frac{8}{( 16 x ^{2} + 1 ) ^{2}} d x

What is the derivative of (5x/(x+4)) ?
The derivative of (5x/(x+4)) is (20)/((x+4)^2)
What is the first derivative of (5x/(x+4)) ?
The first derivative of (5x/(x+4)) is (20)/((x+4)^2)