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Popular >

y^'=2xy+x

Solution

y^{^{'}} = 2 x y + x

Solution

y = \frac{e ^{x^{2} + c_{1}}}{2} - \frac{1}{2}

Solution steps

y^{'} (x) = 2 x y + x

Solve separable ODE:

y = \frac{e ^{x^{2} + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{x^{2} + c_{1}}}{2} - \frac{1}{2}

Graph

Popular Examples

derivative of (2x-1^{3/2})

\frac{d}{d x} ((2 x - 1)^{\frac{3}{2}})

derivative of e^{7x}(7x-1)^8 derivative of

e^{7 x} (7 x - 1)^{8}

integral of 2^x*sin(3x)

\int 2^{x} \cdot sin (3 x) d x

sum from n=1 to infinity of 6/(sqrt(n))

n = 1 \sum \infty \frac{6}{n}

sum from n=1 to infinity of 1/(n^{7/2)}

n = 1 \sum \infty \frac{1}{n ^{\frac{7}{2}}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=2xy+x ?
The solution for y^'=2xy+x is y=(e^{x^2+c_{1}})/2-1/2