What is the derivative of 3x+x^2 ?

The derivative of 3x+x^2 is 3+2x

What is the first derivative of 3x+x^2 ?

The first derivative of 3x+x^2 is 3+2x

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\frac{d}{d x} (3 x + x^{2})

3 + 2 x

Solution steps

\frac{d}{d x} (3 x + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (x^{2}) = 2 x

= 3 + 2 x

\int 4 x cos (9 x) d x

\frac{d}{d x} (\frac{1}{8} ln (\frac{3 x - 4}{3 x + 4}))

\frac{\partial}{\partial x} (- x^{3} + 4 x y - 2 y^{2} + 1)

x \to 7 lim (2 x + 5)

\frac{d}{d x} ((x + 4)^{2})